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n^2-1n-110=0
a = 1; b = -1; c = -110;
Δ = b2-4ac
Δ = -12-4·1·(-110)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-21}{2*1}=\frac{-20}{2} =-10 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+21}{2*1}=\frac{22}{2} =11 $
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